### Classes como tipos

Você também pode declarar uma classe como o tipo de uma variável.

Digamos que você tenha uma classe `Person`, com um nome:

```Python hl_lines="1-3"
{!../../docs_src/python_types/tutorial010.py!}
```

Então você pode declarar que uma variável é do tipo `Person`:

```Python hl_lines="6"
{!../../docs_src/python_types/tutorial010.py!}
```

### Das Problem reproduzieren

In den meisten Fällen und bei den meisten Fragen ist etwas mit dem von der Person erstellten **eigenen Quellcode** los.

In vielen Fällen wird nur ein Fragment des Codes gepostet, aber das reicht nicht aus, um **das Problem zu reproduzieren**.

		if info.Person == nil {
			t.Fatalf("Failed, expected not nil, got person nil")
		}
		if info.Address == nil {
			t.Fatalf("Failed, expected not nil, got address nil")
		}
		if info.Person.ID == person1.ID {
			personMatched = true
			if info.Person.Name != person1.Name {
				t.Errorf("Failed, expected %v, got %v", person1.Name, info.Person.Name)
			}
		}

////

### Klassen als Typen

Sie können auch eine Klasse als Typ einer Variablen deklarieren.

Nehmen wir an, Sie haben eine Klasse `Person`, mit einem Namen:

```Python hl_lines="1-3"
{!../../docs_src/python_types/tutorial010.py!}
```

Dann können Sie eine Variable vom Typ `Person` deklarieren:

```Python hl_lines="6"
{!../../docs_src/python_types/tutorial010.py!}
```

### Классы как типы

Вы также можете объявить класс как тип переменной.

Допустим, у вас есть класс `Person` с полем `name`:

```Python hl_lines="1-3"
{!../../docs_src/python_types/tutorial010.py!}
```

Тогда вы можете объявить переменную типа `Person`:

```Python hl_lines="6"
{!../../docs_src/python_types/tutorial010.py!}
```

И снова вы получаете полную поддержку редактора:

* ...and others.

////

### Classes as types

You can also declare a class as the type of a variable.

Let's say you have a class `Person`, with a name:

{* ../../docs_src/python_types/tutorial010.py hl[1:3] *}

Then you can declare a variable to be of type `Person`:

{* ../../docs_src/python_types/tutorial010.py hl[6] *}

And then, again, you get all the editor support:

### Lớp như kiểu dữ liệu

Bạn cũng có thể khai báo một lớp như là kiểu dữ liệu của một biến.

Hãy nói rằng bạn muốn có một lớp `Person` với một tên:

```Python hl_lines="1-3"
{!../../docs_src/python_types/tutorial010.py!}
```

Sau đó bạn có thể khai báo một biến có kiểu là `Person`:

```Python hl_lines="6"
{!../../docs_src/python_types/tutorial010.py!}
```

func TestMultipleMany2Many(t *testing.T) {
	type Thing struct {
		ID int
	}

	type Person struct {
		ID       int
		Likes    []Thing `gorm:"many2many:likes"`
		Dislikes []Thing `gorm:"many2many:dislikes"`
	}

	checkStructRelation(t, &Person{},
		Relation{
			Name: "Likes", Type: schema.Many2Many, Schema: "Person", FieldSchema: "Thing",
			JoinTable: JoinTable{Name: "likes", Table: "likes"},

////

### ক্লাস হিসেবে টাইপস

আপনি একটি ভেরিয়েবলের টাইপ হিসেবে একটি ক্লাস ঘোষণা করতে পারেন।

ধরুন আপনার কাছে `Person` নামে একটি ক্লাস আছে, যার একটি নাম আছে:

```Python hl_lines="1-3"
{!../../docs_src/python_types/tutorial010.py!}
```

তারপর আপনি একটি ভেরিয়েবলকে `Person` টাইপের হিসেবে ঘোষণা করতে পারেন:

```Python hl_lines="6"
{!../../docs_src/python_types/tutorial010.py!}
```

  }

  /**
   * Explicitly specifies the return type of this {@code Invokable}. For example:
   *
   * <pre>{@code
   * Method factoryMethod = Person.class.getMethod("create");
   * Invokable<?, Person> factory = Invokable.of(getNameMethod).returning(Person.class);
   * }</pre>
   */
  public final <R1 extends R> Invokable<T, R1> returning(Class<R1> returnType) {
    return returning(TypeToken.of(returnType));
  }