{!> ../../docs_src/dependencies/tutorial001_an.py!}
```

////

//// tab | Python 3.10+ non-Annotated

/// tip | "Dica"

Utilize a versão com `Annotated` se possível.

///

```Python hl_lines="7"
{!> ../../docs_src/dependencies/tutorial001_py310.py!}
```

////

//// tab | Python 3.8+ non-Annotated

/// tip | "Dica"

Utilize a versão com `Annotated` se possível.

///

{!> ../../docs_src/dependencies/tutorial001_an.py!}
```

////

//// tab | Python 3.10+ non-Annotated

/// tip

Prefer to use the `Annotated` version if possible.

///

```Python hl_lines="7"
{!> ../../docs_src/dependencies/tutorial001_py310.py!}
```

////

//// tab | Python 3.8+ non-Annotated

/// tip

Prefer to use the `Annotated` version if possible.

///

```

////

//// tab | Python 3.10+ non-Annotated

/// tip | Dica

Utilize a versão com `Annotated`, se possível

///

```Python hl_lines="7  15"
{!> ../../docs_src/request_files/tutorial001_02_py310.py!}
```

////

//// tab | Python 3.8+ non-Annotated

/// tip | Dica

Utilize a versão com `Annotated`, se possível

///

  // level may borrow at any one time.
  // This field holds the ratio of that limit to the level's nominal
  // concurrency limit. When this field is non-nil, it must hold a
  // non-negative integer and the limit is calculated as follows.
  //
  // BorrowingCL(i) = round( NominalCL(i) * borrowingLimitPercent(i)/100.0 )
  //

		var r rune
		r, width = utf8.DecodeRune(data[i:])
		if isSpace(r) {
			return i + width, data[start:i], nil
		}
	}
	// If we're at EOF, we have a final, non-empty, non-terminated word. Return it.
	if atEOF && len(data) > start {
		return len(data), data[start:], nil
	}
	// Request more data.
	return start, nil, nil

```

////

//// tab | Python 3.10+ non-Annotated

/// tip

Prefer to use the `Annotated` version if possible.

///

```Python hl_lines="7"
{!> ../../docs_src/query_params_str_validations/tutorial003_py310.py!}
```

////

//// tab | Python 3.8+ non-Annotated

/// tip

Prefer to use the `Annotated` version if possible.

///

      // Since index and (dataset.length - 1) are non-negative ints, their product can be expressed
      // as a long, without risk of overflow:
      long numerator = (long) index * (dataset.length - 1);
      // Since scale is a positive int, index is in [0, scale], and (dataset.length - 1) is a
      // non-negative int, we can do long-arithmetic on index * (dataset.length - 1) / scale to get

   *
   * <p>This is guaranteed to return zero if the dataset contains a single pair of finite values. It
   * is not guaranteed to return zero when the dataset consists of the same pair of values multiple
   * times, due to numerical errors.
   *
   * <h3>Non-finite values</h3>
   *
   * <p>If the dataset contains any non-finite values ({@link Double#POSITIVE_INFINITY}, {@link

     * Consequently:
     * 1. If the previous mean is finite and the new value is non-finite then the new mean is that
     *    value (whether it is NaN or infinity).
     * 2. If the new value is finite and the previous mean is non-finite then the mean is unchanged
     *    (whether it is NaN or infinity).
     * 3. If both the previous mean and the new value are non-finite and...

```

////

//// tab | Python 3.10+ non-Annotated

/// tip | Dica

Prefira utilizar a versão `Annotated` se possível.

///

```Python hl_lines="4  8  12  46  64  105  107-115  121-124  128-134  139  155"
{!> ../../docs_src/security/tutorial005_py310.py!}
```

////

//// tab | Python 3.9+ non-Annotated

/// tip | Dica