assertEquals(tree, copyFromTree);
    assertSame(Ordering.natural(), copyFromTree.keyComparator());
    assertSame(Ordering.natural(), copyFromTree.valueComparator());
    assertSame(Ordering.natural(), copyFromTree.get(1.0).comparator());
  }

  /** Test that creating one TreeMultimap from a non-TreeMultimap results in natural ordering. */
  public void testCreateFromHashMultimap() {

  }

  public static <E extends Comparable<? super E>> ImmutableSortedSet<E> of(E e1) {
    return ofInternal(Ordering.natural(), e1);
  }

  @SuppressWarnings("unchecked")
  public static <E extends Comparable<? super E>> ImmutableSortedSet<E> of(E e1, E e2) {
    return ofInternal(Ordering.natural(), e1, e2);
  }

  @SuppressWarnings("unchecked")

    ImmutableTable.Builder<Character, Integer, String> builder = ImmutableTable.builder();
    Table<Character, Integer, String> copy =
        builder
            .orderRowsBy(Ordering.natural())
            .orderColumnsBy(Ordering.natural())
            .putAll(table)
            .build();
    assertThat(copy.rowKeySet()).containsExactly('a', 'b').inOrder();
    assertThat(copy.columnKeySet()).containsExactly(1, 2).inOrder();

 *       directly
 *   <li>Pass a <i>pre-existing</i> {@link Comparator} instance to {@link #from(Comparator)}
 *   <li>Use the natural ordering, {@link Ordering#natural}
 * </ul>
 *
 * <h4>Chaining</h4>
 *
 * <p>Then you can use the <i>chaining</i> methods to get an altered version of that {@code
 * Ordering}, including:
 *
 * <ul>
 *   <li>{@link #reverse}

        .addEqualityGroup(Ordering.natural())
        .testEquals();
    reserializeAndAssert(comparator);
    assertEquals("Ordering.natural().reverse().onResultOf(StringLength)", comparator.toString());
  }

  public void testLexicographical() {
    Ordering<String> ordering = Ordering.natural();
    Ordering<Iterable<String>> lexy = ordering.lexicographical();

        .addEqualityGroup(Ordering.natural())
        .testEquals();
    reserializeAndAssert(comparator);
    assertEquals("Ordering.natural().reverse().onResultOf(StringLength)", comparator.toString());
  }

  public void testLexicographical() {
    Ordering<String> ordering = Ordering.natural();
    Ordering<Iterable<String>> lexy = ordering.lexicographical();

    checkNotNull(e);
    return binarySearch(list, e, Ordering.natural(), presentBehavior, absentBehavior);
  }

  /**
   * Binary searches the list for the specified key, using the specified key function.
   *
   * <p>Equivalent to {@link #binarySearch(List, Function, Object, Comparator, KeyPresentBehavior,
   * KeyAbsentBehavior)} using {@link Ordering#natural}.
   */

   * of their natural ordering.
   */
  public static <E extends Comparable<?>> Builder<E> reverseOrder() {
    return new Builder<>(Collections.reverseOrder());
  }

  /**
   * Returns a builder that creates immutable sorted sets whose elements are ordered by their
   * natural ordering. The sorted sets use {@link Ordering#natural()} as the comparator. This method

      K k1, V v1, K k2, V v2) {
    return new Builder<K, V>(Ordering.natural()).put(k1, v1).put(k2, v2).build();
  }

  public static <K extends Comparable<? super K>, V> ImmutableSortedMap<K, V> of(
      K k1, V v1, K k2, V v2, K k3, V v3) {
    return new Builder<K, V>(Ordering.natural()).put(k1, v1).put(k2, v2).put(k3, v3).build();
  }

import javax.annotation.CheckForNull;

/**
 * Implementation of {@code Table} whose row keys and column keys are ordered by their natural
 * ordering or by supplied comparators. When constructing a {@code TreeBasedTable}, you may provide
 * comparators for the row keys and the column keys, or you may use natural ordering for both.
 *
 * <p>The {@link #rowKeySet} method returns a {@link SortedSet} and the {@link #rowMap} method