String[] keys = entrySet.stream().map(Map.Entry::getKey).toArray(String[]::new);

        assertTrue("Should contain all keys", Arrays.asList(keys).contains("lang"));
        assertTrue("Should contain all keys", Arrays.asList(keys).contains("a_key"));
        assertTrue("Should contain all keys", Arrays.asList(keys).contains("b_key"));
        assertTrue("Should contain all keys", Arrays.asList(keys).contains("c_key"));

        key8[2] = (byte) (((key7[1] & 0x03) << 5 | (key7[2] & 0xff) >> 3 & 0xff) & 0xff);
        key8[3] = (byte) (((key7[2] & 0x07) << 4 | (key7[3] & 0xff) >> 4 & 0xff) & 0xff);
        key8[4] = (byte) (((key7[3] & 0x0F) << 3 | (key7[4] & 0xff) >> 5 & 0xff) & 0xff);
        key8[5] = (byte) (((key7[4] & 0x1F) << 2 | (key7[5] & 0xff) >> 6 & 0xff) & 0xff);
        key8[6] = (byte) (((key7[5] & 0x3F) << 1 | (key7[6] & 0xff) >> 7 & 0xff) & 0xff);

    public void testGenerateRandomKey() {
        byte[] key1 = keyManager.generateRandomKey(32);
        byte[] key2 = keyManager.generateRandomKey(32);

        assertNotNull(key1, "Should generate key 1");
        assertNotNull(key2, "Should generate key 2");
        assertEquals(32, key1.length, "Key 1 should have correct length");
        assertEquals(32, key2.length, "Key 2 should have correct length");

	lru := lru.NewLRU[string, int](2, nil, time.Hour)
	lru.Add("key1", 1)
	lru.Add("key2", 2)
	lru.Add("key3", 3)

	if _, ok := lru.Get("key1"); ok {
		t.Errorf("Expected key1 to be removed, but it still exists")
	}
}

func TestLRU_Add_UnlimitedSize_NoEviction(t *testing.T) {
	lru := lru.NewLRU[string, int](0, nil, time.Hour)
	lru.Add("key1", 1)
	lru.Add("key2", 2)
	lru.Add("key3", 3)

	if _, ok := lru.Get("key1"); !ok {

 * i.e. {@code if (key1.equals(key2))} then {@code striped.get(key1) == striped.get(key2)} (assuming
 * {@link Object#hashCode()} is correctly implemented for the keys). Note that if {@code key1} is
 * <strong>not</strong> equal to {@code key2}, it is <strong>not</strong> guaranteed that {@code

 * {@link #entries()}. Unlike {@link LinkedHashMultimap}, the iteration order is kept consistent
 * between keys, entries and values. For example, calling:
 *
 * {@snippet :
 * multimap.remove(key1, foo);
 * }
 *
 * <p>changes the entries iteration order to {@code [key2=bar, key1=baz]} and the key iteration
 * order to {@code [key2, key1]}. The {@link #entries()} iterator returns mutable map entries, and

        // Then - all keys should be different from each other
        assertFalse(Arrays.equals(signingKey, appKey), "Signing and application keys should be different");
        assertFalse(Arrays.equals(signingKey, encKey), "Signing and encryption keys should be different");
        assertFalse(Arrays.equals(signingKey, decKey), "Signing and decryption keys should be different");

      keys.remove(1);
      keys.remove(2);
      assertFalse(keys.remove(null));
      assertFalse(keys.remove(6));
      assertFalse(keys.remove(-6));
      assertFalse(keys.removeAll(asList(null, 0, 15, 1500)));
      assertFalse(keys.retainAll(asList(null, 0, 15, 1500)));
      checkEmpty(keys);
      checkEmpty(cache);
    }
  }

   * either key is null or isn't among the keys provided during construction, this method has no
   * effect.
   *
   * <p>This method is equivalent to {@code put(rowKey, columnKey, null)} when both provided keys
   * are valid.
   *
   * @param rowKey row key of mapping to be erased
   * @param columnKey column key of mapping to be erased

    }

    /**
     * Generate a random key
     *
     * @param length key length in bytes
     * @return random key bytes
     */
    public byte[] generateRandomKey(int length) {
        checkNotClosed();

        byte[] key = new byte[length];
        secureRandom.nextBytes(key);
        return key;
    }

    /**
     * Clear all stored keys
     */
    public void clearAllKeys() {