this.bitCount = LongAddables.create();
    }

    // Used by serialization
    LockFreeBitArray(long[] data) {
      checkArgument(data.length > 0, "data length is zero!");
      this.data = new AtomicLongArray(data);
      this.bitCount = LongAddables.create();
      long bitCount = 0;
      for (long value : data) {
        bitCount += Long.bitCount(value);
      }

      sink.writeByte(accumulator.toInt())
    }
  }

  fun encodedLength(bytes: ByteString): Int {
    var bitCount = 0L

    for (i in 0 until bytes.size) {
      val byteIn = bytes[i] and 0xff
      bitCount += CODE_BIT_COUNTS[byteIn].toLong()
    }

    return ((bitCount + 7) shr 3).toInt() // Round up to an even byte.
  }

  fun decode(
    source: BufferedSource,
    byteCount: Long,

   *
   * @since 22.0
   */
  public long approximateElementCount() {
    long bitSize = bits.bitSize();
    long bitCount = bits.bitCount();

    /*
     * Each insertion is expected to reduce the # of clear bits by a factor of
     * `numHashFunctions/bitSize`. So, after n insertions, expected bitCount is `bitSize * (1 - (1 -
     * numHashFunctions/bitSize)^n)`. Solving that for n, and approximating `ln x` as `x - 1` when x

            assertEquals(1, Integer.bitCount(DcerpcConstants.DCERPC_CONC_MPX), "DCERPC_CONC_MPX should be a single bit");
            assertEquals(1, Integer.bitCount(DcerpcConstants.DCERPC_DID_NOT_EXECUTE), "DCERPC_DID_NOT_EXECUTE should be a single bit");
            assertEquals(1, Integer.bitCount(DcerpcConstants.DCERPC_MAYBE), "DCERPC_MAYBE should be a single bit");

    checkPositive("x", x);
    return Integer.highestOneBit(x);
  }

  /**
   * Returns {@code true} if {@code x} represents a power of two.
   *
   * <p>This differs from {@code Integer.bitCount(x) == 1}, because {@code
   * Integer.bitCount(Integer.MIN_VALUE) == 1}, but {@link Integer#MIN_VALUE} is not a power of two.
   */
  // Whenever both tests are cheap and functional, it's faster to use &, | instead of &&, ||

  public void testIsPowerOfTwo() {
    for (int x : ALL_INTEGER_CANDIDATES) {
      // Checks for a single bit set.
      BigInteger bigX = BigInteger.valueOf(x);
      boolean expected = (bigX.signum() > 0) && (bigX.bitCount() == 1);
      assertEquals(expected, IntMath.isPowerOfTwo(x));
    }
  }

  public void testLog2ZeroAlwaysThrows() {
    for (RoundingMode mode : ALL_ROUNDING_MODES) {

  public void testIsPowerOfTwo() {
    for (int x : ALL_INTEGER_CANDIDATES) {
      // Checks for a single bit set.
      BigInteger bigX = BigInteger.valueOf(x);
      boolean expected = (bigX.signum() > 0) && (bigX.bitCount() == 1);
      assertEquals(expected, IntMath.isPowerOfTwo(x));
    }
  }

  public void testLog2ZeroAlwaysThrows() {
    for (RoundingMode mode : ALL_ROUNDING_MODES) {

    return 1L << ((Long.SIZE - 1) - Long.numberOfLeadingZeros(x));
  }

  /**
   * Returns {@code true} if {@code x} represents a power of two.
   *
   * <p>This differs from {@code Long.bitCount(x) == 1}, because {@code
   * Long.bitCount(Long.MIN_VALUE) == 1}, but {@link Long#MIN_VALUE} is not a power of two.
   */
  // Whenever both tests are cheap and functional, it's faster to use &, | instead of &&, ||

  public void testIsPowerOfTwo() {
    for (long x : ALL_LONG_CANDIDATES) {
      // Checks for a single bit set.
      BigInteger bigX = BigInteger.valueOf(x);
      boolean expected = (bigX.signum() > 0) && (bigX.bitCount() == 1);
      assertEquals(expected, LongMath.isPowerOfTwo(x));
    }
  }

  public void testLog2ZeroAlwaysThrows() {
    for (RoundingMode mode : ALL_ROUNDING_MODES) {

        this.clientIp = value;
    }

    public Long getHitCount() {
        checkSpecifiedProperty("hitCount");
        return hitCount;
    }

    public void setHitCount(Long value) {
        registerModifiedProperty("hitCount");
        this.hitCount = value;
    }

    public String getHitCountRelation() {
        checkSpecifiedProperty("hitCountRelation");