of classes Classes of layer : Classes and Packages Click on or to go to the cycle to which the class/package belongs. Class/Package Size Used by Uses internal Uses external Layer Source(s) # Member of cycle Classes using : uses: true uses: Packages using : uses: true uses: Classes of cycle : Best fragmenter(s) of cycle : Center classes of cycle : Packages of cycle : Best fragmenter(s) of cycle : Center packages of cycle : cursor:pointer; javascript:showTable(" ",""," ; ") cursor:pointer; javascript:showTable("...

 *       verified or created.
 *   <li>If a new edge needs to be created, the outgoing edges of the acquired locks are traversed
 *       to check for a cycle that reaches the lock to be acquired. If no cycle is detected, a new
 *       "safe" edge is created.
 *   <li>If a cycle is detected, an "unsafe" (cyclic) edge is created to represent a potential
 *       deadlock situation, and the appropriate Policy is executed.
 * </ul>
 *

       *
       * Maybe there is a way to avoid this cycle. But we think the cycle is safe enough to ignore:
       * Each task is retained for only as long as it is running -- so it's retained only as long as
       * it would already be retained by the underlying executor.
       *
       * If the cycle test starts reporting this cycle in the future, we should add an entry to
       * cycle_suppress_list.txt.
       */

	minSleep time.Duration

	// cycle will be closed
	cycle chan struct{}

	// isScanner should be set when this is used by the scanner
	// to record metrics.
	isScanner bool
}

// newDynamicSleeper
func newDynamicSleeper(factor float64, maxWait time.Duration, isScanner bool) *dynamicSleeper {
	return &dynamicSleeper{
		factor:    factor,
		cycle:     make(chan struct{}),
		maxSleep:  maxWait,

    // always point to "a".
    assertThat(cycle.iterator().next()).isEqualTo("a");
  }

  public void testCycle_emptyIterable() {
    FluentIterable<Integer> cycle = FluentIterable.<Integer>of().cycle();
    assertFalse(cycle.iterator().hasNext());
  }

  public void testCycle_removingAllElementsStopsCycle() {
    FluentIterable<Integer> cycle = fluent(1, 2).cycle();
    Iterator<Integer> iterator = cycle.iterator();

// Use of this source code is governed by a BSD-style
// license that can be found in the LICENSE file.

TEXT errors(SB),$0
	CSRRC	(X10), CYCLE, X5		// ERROR "integer register or immediate expected for 1st operand"
	CSRRC	X0, TU, X5			// ERROR "unknown CSR"
	CSRRC	X0, CYCLE			// ERROR "missing CSR name"
	CSRRC	X0, CYCLE, (X10)		// ERROR "needs an integer register output"
	CSRRC	$-1, TIME, X15			// ERROR "immediate out of range 0 to 31"

  }

  public void testConcat_infiniteIterable() throws IOException {
    CharSource source = CharSource.wrap("abcd");
    Iterable<CharSource> cycle = Iterables.cycle(ImmutableList.of(source));
    CharSource concatenated = CharSource.concat(cycle);

    String expected = "abcdabcd";

    // read the first 8 chars manually, since there's no equivalent to ByteSource.slice

   * elements.
   *
   * <p>To cycle over the iterable {@code n} times, use the following: {@code
   * Iterables.concat(Collections.nCopies(n, iterable))}
   *
   * <p><b>Java 8+ users:</b> The {@code Stream} equivalent of this method is {@code
   * Stream.generate(() -> iterable).flatMap(Streams::stream)}.
   */
  public static <T extends @Nullable Object> Iterable<T> cycle(Iterable<T> iterable) {
    checkNotNull(iterable);

// mod returns true if the hash mod cycles == cycle.
// If cycles is 0 false is always returned.
// If cycles is 1 true is always returned (as expected).
func (h dataUsageHash) mod(cycle uint32, cycles uint32) bool {
	if cycles <= 1 {
		return cycles == 1
	}
	return uint32(xxhash.Sum64String(string(h)))%cycles == cycle%cycles
}

// modAlt returns true if the hash mod cycles == cycle.
// This is out of sync with mod.

      }
      // First, check whether var -> arg forms a cycle
      for (Type t = arg; t != null; t = mappings.get(TypeVariableKey.forLookup(t))) {
        if (var.equalsType(t)) {
          // cycle detected, remove the entire cycle from the mapping so that
          // each type variable resolves deterministically to itself.
          // Otherwise, an F -> T cycle will end up resolving both F and T