}

  public void testIsConnected() {
    assertTrue(Range.closed(3, 5).isConnected(Range.open(5, 6)));
    assertTrue(Range.closed(3, 5).isConnected(Range.closed(5, 6)));
    assertTrue(Range.closed(5, 6).isConnected(Range.closed(3, 5)));
    assertTrue(Range.closed(3, 5).isConnected(Range.openClosed(5, 5)));
    assertTrue(Range.open(3, 5).isConnected(Range.closed(5, 6)));

        .inOrder();
  }

  public void testRemovePartSharingLowerBound() {
    TreeRangeSet<Integer> rangeSet = TreeRangeSet.create();
    rangeSet.add(Range.closed(3, 5));
    rangeSet.remove(Range.closedOpen(3, 5));
    testInvariants(rangeSet);
    assertThat(rangeSet.asRanges()).contains(Range.singleton(5));
    assertThat(rangeSet.complement().asRanges())

                    return new SampleElements<>(
                        mapEntry(Range.singleton(0), "banana"),
                        mapEntry(Range.closedOpen(3, 5), "frisbee"),
                        mapEntry(Range.atMost(-1), "fruitcake"),
                        mapEntry(Range.open(10, 15), "elephant"),
                        mapEntry(Range.closed(20, 22), "umbrella"));

   * enclosed} by both this range and {@code other}.
   *
   * <p>For example,
   *
   * <ul>
   *   <li>{@code [2, 4)} and {@code [5, 7)} are not connected
   *   <li>{@code [2, 4)} and {@code [3, 5)} are connected, because both enclose {@code [3, 4)}
   *   <li>{@code [2, 4)} and {@code [4, 6)} are connected, because both enclose the empty range
   *       {@code [4, 4)}
   * </ul>
   *

        (byte) 0, (byte)57, (byte)49, (byte)41, (byte)33, (byte)25, (byte)17,
        (byte) 9, (byte) 1, (byte)58, (byte)50, (byte)42, (byte)34, (byte)26,
        (byte)18, (byte)10, (byte) 2, (byte)59, (byte)51, (byte)43, (byte)35,
        (byte)62, (byte)54, (byte)46, (byte)38, (byte)30, (byte)22, (byte)14,
        (byte) 6, (byte)61, (byte)53, (byte)45, (byte)37, (byte)29, (byte)21,

   * enclosed} by both this range and {@code other}.
   *
   * <p>For example,
   *
   * <ul>
   *   <li>{@code [2, 4)} and {@code [5, 7)} are not connected
   *   <li>{@code [2, 4)} and {@code [3, 5)} are connected, because both enclose {@code [3, 4)}
   *   <li>{@code [2, 4)} and {@code [4, 6)} are connected, because both enclose the empty range
   *       {@code [4, 4)}
   * </ul>
   *

              }
            ]
          },
          "unit": "bytes"
        },
        "overrides": []
      },
      "gridPos": {
        "h": 7,
        "w": 6,
        "x": 0,
        "y": 35
      },
      "id": 72,
      "links": [],
      "options": {
        "legend": {
          "calcs": [],
          "displayMode": "list",
          "placement": "bottom",
          "showLegend": true

    assertFalse(rangeSet.encloses(Range.greaterThan(5)));

    RangeSet<Integer> expectedComplement =
        ImmutableRangeSet.<Integer>builder()
            .add(Range.lessThan(1))
            .add(Range.closedOpen(3, 5))
            .add(Range.greaterThan(8))
            .build();

    assertEquals(expectedComplement, rangeSet.complement());
  }

  public void testMultipleBoundedBelowRanges() {

                'capabilities excluding version %s.' % ver)
          all_valid = False
        if ver < 3.5:
          print('WARNING: XLA does not support CUDA compute capabilities '
                'lower than 3.5. Disable XLA when running on older GPUs.')

    if all_valid:
      break

    # Reset and Retry

                          /* inch forward 1 byte and try again */
            for (int i = 0; i < 35; i++) {
                sbuf[i] = sbuf[i + 1];
            }
            int b;
            if ((b = in.read()) == -1) return null;
            sbuf[35] = (byte)b;
        }

        key.mid = Encdec.dec_uint16le( sbuf, 34 ) & 0xFFFF;