return b == addressOffset + 4
}

/** Encodes an IPv6 address in canonical form according to RFC 5952. */
internal fun inet6AddressToAscii(address: ByteArray): String {
  // Go through the address looking for the longest run of 0s. Each group is 2-bytes.
  // A run must be longer than one group (section 4.2.2).
  // If there are multiple equal runs, the first one must be used (section 4.2.3).
  var longestRunOffset = -1

    for (policy in addressStates.values) {
      policy.scheduleOpener()
    }
  }

  /**
   * Performs maintenance on this pool, evicting the connection that has been idle the longest if
   * either it has exceeded the keep alive limit or the idle connections limit.
   *
   * Returns the duration in nanoseconds to sleep until the next scheduled call to this method.

    for (n = len; n < size - n; n <<= 1) {
      System.arraycopy(array, 0, array, n, n);
    }
    System.arraycopy(array, 0, array, n, size - n);
    return new String(array);
  }

  /**
   * Returns the longest string {@code prefix} such that {@code a.toString().startsWith(prefix) &&
   * b.toString().startsWith(prefix)}, taking care not to split surrogate pairs. If {@code a} and
   * {@code b} have no common prefix, returns the empty string.

    // Start by looking for exact matches. We start at the leftmost label. For example, foo.bar.com
    // will look like: [foo, bar, com], [bar, com], [com]. The longest matching rule wins.
    var exactMatch: String? = null
    for (i in domainLabelsUtf8Bytes.indices) {
      val rule = publicSuffixListBytes.binarySearch(domainLabelsUtf8Bytes, i)
      if (rule != null) {

/**
 * A bounded {@linkplain BlockingQueue blocking queue} backed by an array. This queue orders
 * elements FIFO (first-in-first-out). The head of the queue is that element that has been
 * on the queue the longest time. The tail of the queue is that element that has been on
 * the queue the shortest time. New elements are inserted at the tail of the queue, and the queue
 * retrieval operations obtain elements at the head of the queue.

/**
 * A bounded {@linkplain BlockingQueue blocking queue} backed by an array. This queue orders
 * elements FIFO (first-in-first-out). The head of the queue is that element that has been
 * on the queue the longest time. The tail of the queue is that element that has been on
 * the queue the shortest time. New elements are inserted at the tail of the queue, and the queue
 * retrieval operations obtain elements at the head of the queue.

            log.trace("No match for domain based root, checking standalone " + domain);
        }
        /*
         * We did not match a domain based root. Now try to match the
         * longest path in the list of stand-alone referrals.
         */

        CacheEntry<DfsReferralDataInternal> refs;
        synchronized ( this.referralsLock ) {
            refs = this.referrals;

    }
    compressLongestRunOfZeroes(hextets);
    return hextetsToIPv6String(hextets);
  }

  /**
   * Identify and mark the longest run of zeroes in an IPv6 address.
   *
   * <p>Only runs of two or more hextets are considered. In case of a tie, the leftmost run wins. If
   * a qualifying run is found, its hextets are replaced by the sentinel value -1.

func restQueries(keys ...string) []string {
	var accumulator []string
	for _, key := range keys {
		accumulator = append(accumulator, key, "{"+key+":.*}")
	}
	return accumulator
}

// Suffix returns the longest common suffix of the provided strings
func lcpSuffix(strs []string) string {
	return lcp(strs, false)
}

func lcp(strs []string, pre bool) string {
	// short-circuit empty list
	if len(strs) == 0 {