builder.put(k1, v1);
    return builder.build();
  }

  /**
   * Returns an immutable multimap containing the given entries, in order. Repeated occurrences of
   * an entry (according to {@link Object#equals}) after the first are ignored.
   */
  public static <K, V> ImmutableSetMultimap<K, V> of(K k1, V v1, K k2, V v2) {

   * order of the returned multiset matches that of the element set of {@code multiset1} followed by
   * the members of the element set of {@code multiset2} that are not contained in {@code
   * multiset1}, with repeated occurrences of the same element appearing consecutively.
   *
   * <p>Results are undefined if {@code multiset1} and {@code multiset2} are based on different

      this.inputList = ImmutableList.sortedCopyOf(comparator, input);
      this.comparator = comparator;
      this.size = calculateSize(inputList, comparator);
    }

    /**
     * The number of permutations with repeated elements is calculated as follows:
     *
     * <ul>
     *   <li>For an empty list, it is 1 (base case).
     *   <li>When r numbers are added to a list of n-r elements, the number of permutations is

   * process in any way, for example being sent over RPC, or saved to disk. For a general-purpose,
   * non-cryptographic hash function that will never change behavior, we suggest {@link
   * #murmur3_128}.
   *
   * <p>Repeated calls to this method on the same loaded {@code Hashing} class, using the same value
   * for {@code minimumBits}, will return identically-behaving {@link HashFunction} instances.
   *

     *
     * <p>In the current implementation, all values associated with a given key are stored in the
     * {@code Builder} object, even though only one of them will be used in the built map. If there
     * can be many repeated keys, it may be more space-efficient to use a {@link
     * java.util.LinkedHashMap LinkedHashMap} and {@link ImmutableMap#copyOf(Map)} rather than
     * {@code ImmutableMap.Builder}.
     *
     * @since 31.1
     */

      this.inputList = ImmutableList.sortedCopyOf(comparator, input);
      this.comparator = comparator;
      this.size = calculateSize(inputList, comparator);
    }

    /**
     * The number of permutations with repeated elements is calculated as follows:
     *
     * <ul>
     *   <li>For an empty list, it is 1 (base case).
     *   <li>When r numbers are added to a list of n-r elements, the number of permutations is

    }
  }

  public void testConcatPeformingFiniteCycle() {
    Iterable<Integer> iterable = asList(1, 2, 3);
    int n = 4;
    Iterable<Integer> repeated = Iterables.concat(Collections.nCopies(n, iterable));
    assertThat(repeated).containsExactly(1, 2, 3, 1, 2, 3, 1, 2, 3, 1, 2, 3).inOrder();
  }

  public void testPartition_badSize() {
    Iterable<Integer> source = Collections.singleton(1);
    try {

    }
  }

  public void testConcatPeformingFiniteCycle() {
    Iterable<Integer> iterable = asList(1, 2, 3);
    int n = 4;
    Iterable<Integer> repeated = Iterables.concat(Collections.nCopies(n, iterable));
    assertThat(repeated).containsExactly(1, 2, 3, 1, 2, 3, 1, 2, 3, 1, 2, 3).inOrder();
  }

  public void testPartition_badSize() {
    Iterable<Integer> source = Collections.singleton(1);
    try {

    assertTrue(Iterables.elementsEqual(LegacyComparable.VALUES_FORWARD, set));
  }

  public void testLegacyComparable_builder_natural() {
    // Note: IntelliJ wrongly reports an error for this statement
    ImmutableSortedSet.Builder<LegacyComparable> builder =
        ImmutableSortedSet.<LegacyComparable>naturalOrder();

    builder.addAll(LegacyComparable.VALUES_BACKWARD);