* {@code asMap} has a few subtleties. As long as the set of keys remains unchanged, adding or
 * removing mappings does not affect the key iteration order. However, if you remove all values
 * associated with a key and then add the key back to the multimap, that key will come last in the
 * key iteration order.
 *
 * <p>The multimap does not store duplicate key-value pairs. Adding a new key-value pair equal to an
 * existing key-value pair has no effect.
 *

            ImmutableList.of("A"),
            ImmutableList.of("A"),
            ImmutableList.of("A", "A", "B", "C"),
            ImmutableList.of("A", "A", "D", "E", "B", "C"));

    String format = "Adding %s at %s";
    for (int i = 0; i < toAdd.size(); i++) {
      int index = indexes.get(i);
      Iterable<String> iterableToAdd = toAdd.get(i);
      boolean expectedChanged = iterableToAdd.iterator().hasNext();

        if (result[0] == 0) {
          distinctElements++;
        }
        this.totalCount += count;
        return (right.height == initHeight) ? this : rebalance();
      }

      // adding count to me!  No rebalance possible.
      result[0] = elemCount;
      long resultCount = (long) elemCount + count;
      checkArgument(resultCount <= Integer.MAX_VALUE);
      this.elemCount += count;

        /*
         * lowasser, 2015-Feb-12: Benchmarks suggest that changing this to UnsignedLongs.remainder
         * and increasing the threshold to 2^32 doesn't pay for itself, and adding another enum
         * constant hurts performance further -- I suspect because bimorphic implementation is a
         * sweet spot for the JVM.
         */
        return (a * b) % m;
      }

            Collections.singletonList("A"),
            ImmutableList.of("A"),
            ImmutableList.of("A", "A", "B", "C"),
            ImmutableList.of("A", "A", "D", "E", "B", "C"));

    String format = "Adding %s at %s";
    for (int i = 0; i < toAdd.size(); i++) {
      int index = indexes.get(i);
      Iterable<String> iterableToAdd = toAdd.get(i);
      boolean expectedChanged = iterableToAdd.iterator().hasNext();

              return oldValue;
            }
          } catch (ArithmeticException overflow) {
            throw new IllegalArgumentException(
                "Overflow adding " + occurrences + " occurrences to a count of " + oldValue);
          }
        } else {
          // In the case of a concurrent remove, we might observe a zero value, which means another

  }

  // LinkedList

  /**
   * Creates a <i>mutable</i>, empty {@code LinkedList} instance (for Java 6 and earlier).
   *
   * <p><b>Note:</b> if you won't be adding any elements to the list, use {@link ImmutableList#of()}
   * instead.
   *
   * <p><b>Performance note:</b> {@link ArrayList} and {@link java.util.ArrayDeque} consistently

  public static class Builder<C extends Comparable<?>> {
    private final List<Range<C>> ranges;

    public Builder() {
      this.ranges = Lists.newArrayList();
    }

    // TODO(lowasser): consider adding union, in addition to add, that does allow overlap

    /**
     * Add the specified range to this builder. Adjacent ranges are permitted and will be merged,

  public static class Builder<C extends Comparable<?>> {
    private final List<Range<C>> ranges;

    public Builder() {
      this.ranges = Lists.newArrayList();
    }

    // TODO(lowasser): consider adding union, in addition to add, that does allow overlap

    /**
     * Add the specified range to this builder. Adjacent ranges are permitted and will be merged,

      public OutputStream openStream() throws IOException {
        return encodingStream(encodedSink.openStream());
      }
    };
  }

  // TODO(lowasser): document the extent of leniency, probably after adding ignore(CharMatcher)

  private static byte[] extract(byte[] result, int length) {
    if (length == result.length) {
      return result;
    }
    byte[] trunc = new byte[length];