NodeConnection(N node) {
      this.node = checkNotNull(node);
    }

    static final class Pred<N> extends NodeConnection<N> {
      Pred(N node) {
        super(node);
      }

      @Override
      public boolean equals(@CheckForNull Object that) {
        if (that instanceof Pred) {
          return this.node.equals(((Pred<?>) that).node);
        } else {
          return false;
        }
      }

        final String pref = ComponentUtil.getFessConfig().getQueryJsonDefaultPreference();
        if (PREFERENCE_QUERY.equals(pref)) {
            return Integer.toString(query.hashCode());
        }
        if (StringUtil.isNotBlank(pref)) {
            return pref;
        }
        return null;
    }

   * the order of a depth-first pre-order traversal. "Pre-order" implies that nodes appear in the
   * {@code Iterable} in the order in which they are first visited.
   *
   * <p><b>Example:</b> The following graph with {@code startNode} {@code a} would return nodes in
   * the order {@code abecfd} (assuming successors are returned in alphabetical order).
   *
   * <pre>{@code
   * b ---- a ---- d
   * |      |

    InputStream in = new ByteArrayInputStream(PRE_FILLED_100);
    byte[] b = ByteStreams.toByteArray(in, 100);
    assertThat(b).isEqualTo(PRE_FILLED_100);
  }

  public void testToByteArray_withSize_givenSmallerSize() throws IOException {
    InputStream in = new ByteArrayInputStream(PRE_FILLED_100);
    byte[] b = ByteStreams.toByteArray(in, 80);
    assertThat(b).isEqualTo(PRE_FILLED_100);
  }

    }
    checkElementsNotNull(contents, n);
    Arrays.sort(contents, 0, n, comparator);
    int uniques = 1;
    for (int i = 1; i < n; i++) {
      E cur = contents[i];
      E prev = contents[uniques - 1];
      if (comparator.compare(cur, prev) != 0) {
        contents[uniques++] = cur;
      }
    }
    Arrays.fill(contents, uniques, n, null);
    return new RegularImmutableSortedSet<>(

 *
 * <pre>{@code
 * ContiguousSet.create(Range.closed(5, 42), DiscreteDomain.integers())
 * }</pre>
 *
 * <p>Note that because bounded ranges over {@code int} and {@code long} values are so common, this
 * particular example can be written as just:
 *
 * <pre>{@code
 * ContiguousSet.closed(5, 42)
 * }</pre>
 *

   * static final} multimaps ("constant multimaps"). Example:
   *
   * <pre>{@code
   * static final Multimap<String, Integer> STRING_TO_INTEGER_MULTIMAP =
   *     new ImmutableListMultimap.Builder<String, Integer>()
   *         .put("one", 1)
   *         .putAll("several", 1, 2, 3)
   *         .putAll("many", 1, 2, 3, 4, 5)
   *         .build();
   * }</pre>
   *

     * represent the same element and count. That is, two entries {@code a} and {@code b} are equal
     * if:
     *
     * <pre>{@code
     * Objects.equal(a.getElement(), b.getElement())
     *     && a.getCount() == b.getCount()
     * }</pre>
     */
    @Override
    // TODO(kevinb): check this wrt TreeMultiset?
    boolean equals(@CheckForNull Object o);

    /**
     * {@inheritDoc}

    checkNotNull(comparator);
    Iterator<? extends T> it = iterable.iterator();
    if (it.hasNext()) {
      T prev = it.next();
      while (it.hasNext()) {
        T next = it.next();
        if (comparator.compare(prev, next) > 0) {
          return false;
        }
        prev = next;
      }
    }
    return true;
  }

  /**

        // not all.  See the test cases for examples on how this can happen.
        try {
          ((Thread) currentRunner).interrupt();
        } finally {
          Runnable prev = getAndSet(DONE);
          if (prev == PARKED) {
            LockSupport.unpark((Thread) currentRunner);
          }
        }
      }
    }
  }

  /**