}
```

#### Desempaquetando un `dict`

Si tomamos un `dict` como `user_dict` y lo pasamos a una función (o clase) con `**user_dict`, Python lo "desempaquetará". Pasará las claves y valores del `user_dict` directamente como argumentos clave-valor.

Así que, continuando con el `user_dict` anterior, escribir:

```Python
UserInDB(**user_dict)
```

sería equivalente a algo como:

```Python
UserInDB(

⚖️ 🌅 ⚫️❔, ⚙️ `user_dict` 🔗, ⏮️ ⚫️❔ 🎚 ⚫️ 💪 ✔️ 🔮:

```Python
UserInDB(
    username = user_dict["username"],
    password = user_dict["password"],
    email = user_dict["email"],
    full_name = user_dict["full_name"],
)
```

#### Pydantic 🏷 ⚪️➡️ 🎚 ➕1️⃣

🖼 🔛 👥 🤚 `user_dict` ⚪️➡️ `user_in.dict()`, 👉 📟:

```Python
user_dict = user_in.dict()
UserInDB(**user_dict)
```

🔜 🌓:

```Python

{* ../../docs_src/security/tutorial003.py hl[80:83] *}

#### 🔃 `**user_dict`

`UserInDB(**user_dict)` ⛓:

*🚶‍♀️ 🔑 & 💲 `user_dict` 🔗 🔑-💲 ❌, 🌓:*

```Python
UserInDB(
    username = user_dict["username"],
    email = user_dict["email"],
    full_name = user_dict["full_name"],
    disabled = user_dict["disabled"],
    hashed_password = user_dict["hashed_password"],
)
```

/// info

}
```

#### Unpacking a `dict` { #unpacking-a-dict }

If we take a `dict` like `user_dict` and pass it to a function (or class) with `**user_dict`, Python will "unpack" it. It will pass the keys and values of the `user_dict` directly as key-value arguments.

So, continuing with the `user_dict` from above, writing:

```Python
UserInDB(**user_dict)
```

would result in something equivalent to:

```Python
UserInDB(

#### About `**user_dict` { #about-user-dict }

`UserInDB(**user_dict)` means:

*Pass the keys and values of the `user_dict` directly as key-value arguments, equivalent to:*

```Python
UserInDB(
    username = user_dict["username"],
    email = user_dict["email"],
    full_name = user_dict["full_name"],
    disabled = user_dict["disabled"],

}
```

#### Desembrulhando um `dict`

Se tomarmos um `dict` como `user_dict` e passarmos para uma função (ou classe) com `**user_dict`, o Python irá "desembrulhá-lo". Ele passará as chaves e valores do `user_dict` diretamente como argumentos chave-valor.

Então, continuando com o `user_dict` acima, escrevendo:

```Python
UserInDB(**user_dict)
```

Resultaria em algo equivalente a:

```Python
UserInDB(

}
```

#### Ein `dict` entpacken

Wenn wir ein `dict` wie `user_dict` nehmen, und es einer Funktion (oder Klassenmethode) mittels `**user_dict` übergeben, wird Python es „entpacken“. Es wird die Schlüssel und Werte von `user_dict` direkt als Schlüsselwort-Argumente übergeben.

Wenn wir also das `user_dict` von oben nehmen und schreiben:

```Python
UserInDB(**user_dict)
```

dann ist das ungefähr äquivalent zu:

```Python

)
```

혹은 더 정확히 말하자면, `user_dict`를 직접 사용하는 것은, 나중에 어떤 값이 추가되더라도 아래와 동일한 효과를 냅니다:

```Python
UserInDB(
    username = user_dict["username"],
    password = user_dict["password"],
    email = user_dict["email"],
    full_name = user_dict["full_name"],
)
```

#### 다른 모델 데이터로 새 Pydantic 모델 생성

위의 예제에서 `user_in.dict()`로부터 `user_dict`를 생성한 것처럼, 아래 코드는:

```Python
user_dict = user_in.dict()

もっと正確に言えば、`user_dict`を将来的にどんな内容であっても直接使用することになります:

```Python
UserInDB(
    username = user_dict["username"],
    password = user_dict["password"],
    email = user_dict["email"],
    full_name = user_dict["full_name"],
)
```

#### 別のモデルからつくるPydanticモデル

上述の例では`user_in.dict()`から`user_dict`をこのコードのように取得していますが:

```Python
user_dict = user_in.dict()
UserInDB(**user_dict)
```

これは以下と同等です:

```Python

        System.out.println(SystemUtil.PATH_SEPARATOR);
        System.out.println(SystemUtil.OS_NAME);
        System.out.println(SystemUtil.JAVA_IO_TMPDIR);
        System.out.println(SystemUtil.USER_DIR);
        System.out.println(SystemUtil.USER_HOME);
    }