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docs/ko/docs/advanced/advanced-python-types.md
```python from typing import Optional def say_hi(name: Optional[str]): print(f"Hey {name}!") ``` 매개변수 `name`은 `Optional[str]`로 정의되어 있지만, 사실 선택적이지 않습니다. 이 매개변수 없이 함수를 호출할 수 없습니다: ```Python say_hi() # 이런, 에러가 발생합니다! 😱 ``` `name` 매개변수는 기본값이 없기 때문에 여전히 필수입니다(선택적이 아님). 대신, `name`에는 `None`을 전달할 수 있습니다: ```Python say_hi(name=None) # 작동합니다. None은 유효합니다 🎉 ```
Created: Sun Apr 05 07:19:11 GMT 2026 - Last Modified: Sat Feb 14 08:57:01 GMT 2026 - 2.4K bytes - Click Count (0) -
docs/zh/docs/advanced/advanced-python-types.md
举个例子,看这段函数: ```python from typing import Optional def say_hi(name: Optional[str]): print(f"Hey {name}!") ``` 参数 `name` 被定义为 `Optional[str]`,但它并不是“可选”的,你不能不传这个参数就调用函数: ```Python say_hi() # 哎呀,这会报错!😱 ``` 参数 `name` 仍然是必填的(不是“可选”),因为它没有默认值。不过,`name` 接受 `None` 作为取值: ```Python say_hi(name=None) # 这样可以,None 是有效的 🎉 ``` 好消息是,在大多数情况下,你可以直接使用 `|` 来定义类型联合: ```python
Created: Sun Apr 05 07:19:11 GMT 2026 - Last Modified: Fri Feb 13 13:37:57 GMT 2026 - 2K bytes - Click Count (0) -
docs/ja/docs/advanced/advanced-python-types.md
例として次の関数を見てみましょう: ```python from typing import Optional def say_hi(name: Optional[str]): print(f"Hey {name}!") ``` パラメータ `name` は `Optional[str]` と定義されていますが、任意ではありません。このパラメータなしで関数を呼び出すことはできません: ```Python say_hi() # あっ、これはエラーになります!😱 ``` `name` パラメータにはデフォルト値がないため、依然として必須(任意ではない)です。ただし、`name` は値として `None` を受け付けます: ```Python say_hi(name=None) # これは動作します。None は有効です 🎉 ```
Created: Sun Apr 05 07:19:11 GMT 2026 - Last Modified: Fri Feb 13 15:24:30 GMT 2026 - 2.4K bytes - Click Count (0) -
docs/en/docs/advanced/advanced-python-types.md
As an example, let's take this function: ```python from typing import Optional def say_hi(name: Optional[str]): print(f"Hey {name}!") ``` The parameter `name` is defined as `Optional[str]`, but it is **not optional**, you cannot call the function without the parameter: ```Python say_hi() # Oh, no, this throws an error! 😱 ```
Created: Sun Apr 05 07:19:11 GMT 2026 - Last Modified: Wed Feb 11 18:32:12 GMT 2026 - 2K bytes - Click Count (0) -
docs/zh-hant/docs/advanced/advanced-python-types.md
from typing import Optional def say_hi(name: Optional[str]): print(f"Hey {name}!") ``` 參數 `name` 被標註為 `Optional[str]`,但它並不是可選的;你不能在沒有該參數的情況下呼叫這個函式: ```Python say_hi() # 糟了,這會拋出錯誤!😱 ``` 參數 `name` 仍是必填(不是可選),因為它沒有預設值。不過,`name` 可以接受 `None` 作為值: ```Python say_hi(name=None) # 這可行,None 是有效的 🎉 ``` 好消息是,多數情況下你可以直接用 `|` 來定義型別聯集: ```python def say_hi(name: str | None): print(f"Hey {name}!")
Created: Sun Apr 05 07:19:11 GMT 2026 - Last Modified: Sat Feb 14 08:15:26 GMT 2026 - 1.9K bytes - Click Count (0) -
docs_src/python_types/tutorial009_py310.py
def say_hi(name: str | None = None): if name is not None: print(f"Hey {name}!") else:Created: Sun Apr 05 07:19:11 GMT 2026 - Last Modified: Fri Jan 07 14:11:31 GMT 2022 - 131 bytes - Click Count (0) -
docs/ru/docs/advanced/advanced-python-types.md
В качестве примера возьмём такую функцию: ```python from typing import Optional def say_hi(name: Optional[str]): print(f"Hey {name}!") ``` Параметр `name` объявлен как `Optional[str]`, но он не является необязательным: вы не можете вызвать функцию без этого параметра: ```Python say_hi() # О нет, это вызывает ошибку! 😱 ```
Created: Sun Apr 05 07:19:11 GMT 2026 - Last Modified: Thu Feb 12 19:57:34 GMT 2026 - 3.3K bytes - Click Count (0) -
docs/tr/docs/advanced/advanced-python-types.md
Örnek olarak şu fonksiyona bakalım: ```python from typing import Optional def say_hi(name: Optional[str]): print(f"Hey {name}!") ``` `name` parametresi `Optional[str]` olarak tanımlıdır; ancak isteğe bağlı değildir, parametre olmadan fonksiyonu çağıramazsınız: ```Python say_hi() # Ah hayır, bu hata fırlatır! 😱 ```
Created: Sun Apr 05 07:19:11 GMT 2026 - Last Modified: Fri Feb 13 12:41:38 GMT 2026 - 2.1K bytes - Click Count (0) -
docs/pt/docs/advanced/advanced-python-types.md
Como exemplo, veja esta função: ```python from typing import Optional def say_hi(name: Optional[str]): print(f"Hey {name}!") ``` O parâmetro `name` é definido como `Optional[str]`, mas não é opcional; não é possível chamar a função sem o parâmetro: ```Python say_hi() # Ah, não, isso gera um erro! 😱 ```
Created: Sun Apr 05 07:19:11 GMT 2026 - Last Modified: Fri Feb 13 13:48:53 GMT 2026 - 2.1K bytes - Click Count (0) -
docs/de/docs/advanced/advanced-python-types.md
Als Beispiel nehmen wir diese Funktion: ```python from typing import Optional def say_hi(name: Optional[str]): print(f"Hey {name}!") ``` Der Parameter `name` ist als `Optional[str]` definiert, aber er ist **nicht optional**, Sie können die Funktion nicht ohne den Parameter aufrufen: ```Python say_hi() # Oh nein, das löst einen Fehler aus! 😱 ```
Created: Sun Apr 05 07:19:11 GMT 2026 - Last Modified: Sat Feb 14 07:57:30 GMT 2026 - 2.3K bytes - Click Count (0)