from starlette.requests import HTTPConnection as HTTPConnection  # noqa: F401

  // Optional: confirm that your app made the HTTP requests you were expecting.
  RecordedRequest request1 = server.takeRequest();
  assertEquals("/v1/chat/messages/", request1.getPath());
  assertNotNull(request1.getHeader("Authorization"));

  RecordedRequest request2 = server.takeRequest();
  assertEquals("/v1/chat/messages/2", request2.getPath());

  RecordedRequest request3 = server.takeRequest();

///

## `Request`-Dokumentation

Weitere Details zum <a href="https://www.starlette.io/requests/" class="external-link" target="_blank">`Request`-Objekt finden Sie in der offiziellen Starlette-Dokumentation</a>.

/// note | "Technische Details"

Sie können auch `from starlette.requests import Request` verwenden.

///

## Documentação do `Request`

Você pode ler mais sobre os detalhes do objeto <a href="https://www.starlette.io/requests/" class="external-link" target="_blank">`Request` no site da documentação oficial do Starlette.</a>.

/// note | "Detalhes Técnicos"

Você também pode utilizar `from starlette.requests import Request`.

但在某些特定情况下，还是需要提取 `Request` 对象。

## 直接使用 `Request` 对象

假设要在*路径操作函数*中获取客户端 IP 地址和主机。

此时，需要直接访问请求。

```Python hl_lines="1  7-8"
{!../../docs_src/using_request_directly/tutorial001.py!}
```

把*路径操作函数*的参数类型声明为 `Request`，**FastAPI** 就能把 `Request` 传递到参数里。

/// tip | "提示"

注意，本例除了声明请求参数之外，还声明了路径参数。

因此，能够提取、验证路径参数、并转换为指定类型，还可以用 OpenAPI 注释。

同样，您也可以正常声明其它参数，而且还可以提取 `Request`。

///

## `Request` 文档

# `Request` class

You can declare a parameter in a *path operation function* or dependency to be of type `Request` and then you can access the raw request object directly, without any validation, etc.

You can import it directly from `fastapi`:

```python
from fastapi import Request
```

/// tip

Ein `Request` hat auch ein `request.receive`, welches eine Funktion ist, die den Hauptteil des Requests empfängt.

Das `scope`-`dict` und die `receive`-Funktion sind beide Teil der ASGI-Spezifikation.

Und diese beiden Dinge, `scope` und `receive`, werden benötigt, um eine neue `Request`-Instanz zu erstellen.

 * governing permissions and limitations under the License.
 */
package org.codelibs.fess.suggest.request;

import org.codelibs.fess.suggest.concurrent.Deferred;
import org.codelibs.fess.suggest.exception.SuggesterException;
import org.opensearch.client.Client;
import org.opensearch.core.common.Strings;

public abstract class Request<T extends Response> {
    public Deferred<T>.Promise execute(final Client client) {

Para aprender mais sobre o `Request` confira a <a href="https://www.starlette.io/requests/" class="external-link" target="_blank">documentação do Starlette sobre Requests</a>.

///

A única coisa que a função retornada por `GzipRequest.get_route_handler` faz de diferente é converter o `Request` para um `GzipRequest`.

🎏 🌌, 👆 💪 📣 🙆 🎏 🔢 🛎, & ➡, 🤚 `Request` 💁‍♂️.

///

## `Request` 🧾

👆 💪 ✍ 🌅 ℹ 🔃 <a href="https://www.starlette.io/requests/" class="external-link" target="_blank">`Request` 🎚 🛂 💃 🧾 🕸</a>.

/// note | "📡 ℹ"

👆 💪 ⚙️ `from starlette.requests import Request`.

**FastAPI** 🚚 ⚫️ 🔗 🏪 👆, 👩‍💻. ✋️ ⚫️ 👟 🔗 ⚪️➡️ 💃.