if l.level == maxBits {
				// All done!
				break
			}
			levels[l.level+1].nextPairFreq = prevFreq + l.lastFreq
			level++
		} else {
			// If we stole from below, move down temporarily to replenish it.
			for levels[level-1].needed > 0 {
				level--
			}
		}
	}

	// Somethings is wrong if at the end, the top level is null or hasn't used
	// all of the leaves.