I        MultiFlag
	PrintOut int
	DebugV   bool
)

func init() {
	flag.Var(&D, "D", "predefined symbol with optional simple value -D=identifier=value; can be set multiple times")
	flag.Var(&I, "I", "include directory; can be set multiple times")
	flag.BoolVar(&DebugV, "v", false, "print debug output")
	flag.Var(objabi.NewDebugFlag(&DebugFlags, nil), "d", "enable debugging settings; try -d help")
	objabi.AddVersionFlag() // -V

query_or_cookie_extractor(["query_or_cookie_extractor"])

read_query["/items/"]

query_extractor --> query_or_cookie_extractor --> read_query
```

## Using the same dependency multiple times

If one of your dependencies is declared multiple times for the same *path operation*, for example, multiple dependencies have a common sub-dependency, **FastAPI** will know to call that sub-dependency only once per request.

// along with this program.  If not, see <http://www.gnu.org/licenses/>.

package cmd

import (
	"os"
	"syscall"
)

var (
	// Disallow updating access times
	// Add non-block to avoid syscall to attempt to set epoll on files.
	readMode = os.O_RDONLY | 0x40000 | syscall.O_NONBLOCK // O_NOATIME

	// Write with data sync only used only for `xl.meta` writes

        "Should be able to peek() first element multiple times", "A", peekingIterator.peek());
    assertEquals(
        "next() should still return first element after peeking", "A", peekingIterator.next());

    assertEquals("Should be able to peek() at middle element", "B", peekingIterator.peek());
    assertEquals(
        "Should be able to peek() middle element multiple times", "B", peekingIterator.peek());
    assertEquals(

    final File file = out.getFile();
    assertEquals(100, file.length());
    assertTrue(file.exists());
    out.close();

    // Make sure that finalize deletes the file
    out = null;

    // times out and throws RuntimeException on failure
    GcFinalization.awaitDone(
        new GcFinalization.FinalizationPredicate() {
          @Override
          public boolean isDone() {
            return !file.exists();

Aqui está um pouco dessa história.

## Alternativas

Eu tenho criado APIs com requisitos complexos por vários anos (Aprendizado de Máquina, sistemas distribuídos, tarefas assíncronas, banco de dados NoSQL etc.), liderando vários times de desenvolvedores.

Como parte disso, eu precisava investigar, testar e usar muitas alternativas.

A história do **FastAPI** é, em grande parte, a história de seus predecessores.

          ascending: true
          exempt-all-milestones: true

          # ISSUES (deactivated) ----------------------------------------------
          # This workflow should touch no issues, so times are set to -1
          # (see actions/stale documentation for the behavior)
          days-before-issue-stale: -1
          stale-issue-label: stale
          stale-issue-message: >

/**
 * A unit of work that can be executed one or more times.
 *
 * Recurrence
 * ----------
 *
 * Tasks control their recurrence schedule. The [runOnce] function returns -1L to signify that the
 * task should not be executed again. Otherwise it returns a delay until the next execution.
 *
 * A task has at most one next execution. If the same task instance is scheduled multiple times, the

        if (node instanceof Element) {
            Element element = (Element) node

            if (indentSelf && depth > 0) {
                target.append('\n')
                depth.times { target.append('    ') }
            }

            target.append("<${element.tagName}")
            for (int i = 0; i < element.attributes.length; i++) {
                Attr attr = element.attributes.item(i)

	for i := 0; i < dynamicTimeoutLogSize; i++ {
		timeout.LogFailure()
	}

	adjustedAgain := timeout.Timeout()

	if initial >= adjusted || adjusted >= adjustedAgain {
		t.Errorf("Failure to increase timeout multiple times")
	}
}

func TestDynamicTimeoutSingleDecrease(t *testing.T) {
	timeout := newDynamicTimeout(time.Minute, time.Second)

	initial := timeout.Timeout()

	for i := 0; i < dynamicTimeoutLogSize; i++ {